Would somebody be able to graph this?

You should have:

a vertex at (1,8)

a y-intercept at (0,6)

a parabola that opens down

and x-intercepts of (-1,0) and (3,0)

Step-by-step explanation:

To get the vertex, you take the number inside the square (h value) and invert the sign for the x value then take the value on the end (k value) and make that the y. For the y-intercept if you let x=0 then the value you get will be the y value at which the graph hits the axis. For the direction in which the parabola opens if the number in front of the square ((x-h)^2 ) is negative it opens down and if it is positive it opens up. For the x-intercepts if you put either number into the function you will get 0.

i have no fu ck ing  clue

Step-by-step explanation:

ifhipufiudsfg

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

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step-by-step explanation: