¿kurt spots a birt sitting at the top of a 40 foot tall telephone pole. if the angle of elevation from the ground where he is standing to the bird is 59 degress, how far is kurt standing from the base of the pole?

Kurt is standing 24.03 ft. from the base of the pole

Step-by-step explanation:

Refer the attached figure .

Height of the pole = AB = 40 ft.

Since the bird is sitting on the top of the pole.

So, the angle of elevation from the ground where Kurt is standing to the bird = ∠ACB = 59°

We are required to find how far is Kurt standing from the base of the pole i.e. BC

So, we will use trigonometric ratio:

Thus BC = 24.03 ft.

Hence, Kurt is standing 24.03 ft. from the base of the pole

it's 24.0 when rounding to the nearest tenth

Step-by-step explanation:

I'm taking a test and this is a question!

eve and marks ratios are equivalent

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl