Acoin is flipped and a random marble is picked from a bag of 10 marbles. two of the marbles in the bag are red. what is the probability of the coin landing on tail and a red marble being drawn? enter your answer as a fraction in simplest form in the box.

A coin flip has a 1/2 probability of landing on tails.

There are 2 red marbles and 10 total marbles.

The probability of picking a red marble would be 2/10, which reduces to 1/5.

The probability of both tails and a red marble would be 1/2 x 1/5 = 1/10

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !