When completing the square, what factor must be added to the quadratic equation 2x2 + 3x – 3 = 0 to solve it?

x = sqrt(33)/4 - 3/4 or x = -3/4 - sqrt(33)/4

Step-by-step explanation:

Solve for x over the real numbers:

2 x^2 + 3 x - 3 = 0

Divide both sides by 2:

x^2 + (3 x)/2 - 3/2 = 0

Add 3/2 to both sides:

x^2 + (3 x)/2 = 3/2

Add 9/16 to both sides:

x^2 + (3 x)/2 + 9/16 = 33/16

Write the left hand side as a square:

(x + 3/4)^2 = 33/16

Take the square root of both sides:

x + 3/4 = sqrt(33)/4 or x + 3/4 = -sqrt(33)/4

Subtract 3/4 from both sides:

x = sqrt(33)/4 - 3/4 or x + 3/4 = -sqrt(33)/4

Subtract 3/4 from both sides:

 x = sqrt(33)/4 - 3/4 or x = -3/4 - sqrt(33)/4

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )