70% of kids who visit a doctor have a fever, and 40% of kids who visit a doctor have a sore throat. if the probability that a kid has a sore throat given that he has a fever is 30%, what is the probability that he has a fever given that he has a sore throat?

52.5%

Step-by-step explanation:

Let A be kids who have a fever, and B be kids who have a sore throat, so

Based on the given information we have

P(A) = 70%, P(B) = 40%, and P(B|A) = 30%   (B|A is read as "B given A", which means probability of B happening given that A has already happened)

We are asked to find P(A|B), the probability of a kid having a fever given that we already know he has a sore throat.

Step 1:  First find P(A and B), this is the probability of a kid having both a fever and a sore throat.  We use the formula

        P(B|A) = P(A and B)/P(A)    

We have 2 of these values listed above, so we plug them in...

       30% = P(A and B)/70%

 This give us a value for P(A and B) which equals 21%  [multiply both sides by 70% to isolate P(A and B), (30%)(70%) = 21%]

Now we flip the equation to P(A|B), which is

     P(A|B) = P(A and B)/P(B)

We have 2 of the values, so we plug them in...

     P(A|B) =  21%/40%

  This gives us a value of 52.5%   (divide 21% by 40%)  

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.