The sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. find the number.

2

Step-by-step explanation:

The question state that;  the sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.

First, we need to interpret and represent this statement mathematically

Let n be the number.

The sum means 'addition'

1/6 of that number is  1/6 of n = 1/6 × n  =

2 1/2 of that number is 2 1/2 of n = 2 1/2 × n  = 5/2 × n =

So the question says that, when we add; ,    and 7 all together, the value is 12 1/2

That is;

 + + 7 = 12 1/2

 + + 7  =         ( changing 12 1/2 to improper fraction will give   )

So we can now go ahead and solve for n

 + + 7  =  

subtract 7 from both-side of the equation

 +   =     -   7

 =  

     =    

 can be reduced to give us

  =  

Cross multiply

8n × 2  = 11× 3

16n = 33

Divide both-side of the equation by 16

   =  

(On the left-hand side of the equation, 16 will cancel-out 16 leaving us with just, while  on the right-hand side of the equation 33 will be divided by 16)

n =       =

Therefore the number is  

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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