Deandre invested his savings in two investment funds. the amount he invested in fund a was twice as much as the amount he invested in fund b. fund a returned a 7% profit and fund b returned a 3% profit. how much did he invest in fund b, if the total profit from the two funds together was $1530?

  $9000

Step-by-step explanation:

Let a and b represent the amounts invested in the two funds. The problem statement gives two relations:

  a = 2b . . . . . . the amount invested in A was twice that invested in B

  7%×a +3%×b = 1530 . . . . . the total profit from the two funds

Substituting for a in the second equation, we have ...

  0.07(2b) + 0.03b = 1530

  0.17b = 1530 . . . . . . . . . . collect terms

  1530/0.17 = b = 9000

Deandre invested $9000 in Fund B.

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

900 degrees

step-by-step explanation: