Ianswered this problem wrong on my calculus bc test. can you guys me figure out the correct answer?

if y = 3x^3 - 2x and dx/dt = 3 , find dy/dt when x = -2.

Step-by-step explanation:

It was given that;

When we differentiate this function with respect to x, we get;

When , we get;

Also we were given that;

.

Recall the chain rule;

We substitute these values into the formula to get;

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9