If the farmer has 234 feet of fencing, what are the dimensions of the region which enclose the maximal area?

Step-by-step explanation:

Lets suppose the area to be enclosed is a square and let the side be s.

The perimeter would be 234 feet.

Perimeter of square is = 4 x side

We get;

Dividing both sides by 4;

s = 58.5 feet

Now, area of the square = side x side

So, the maximum area that can be enclosed is = square feet

Hence, the dimensions will be 58.5 feet by 58.5 feet.

zero

step-by-step explanation:

f(2)= x-2

plug in the 2 in the "x"

f(2)=2-2

f(2)=0