Mathematics, 21.09.2019 19:30 millernicholas622
Find the point, m, that divides segment ab into a ratio of 2: 1 if a is at (-1, 2) and b is at (8, 15).
Answers: 1
![\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ A(-1,2)\qquad B(8,15)\qquad \qquad \stackrel{\textit{ratio from A to B}}{2:1} \\\\\\ \cfrac{A\underline{M}}{\underline{M} B} = \cfrac{2}{1}\implies \cfrac{A}{B} = \cfrac{2}{1}\implies 1A=2B\implies 1(-1,2)=2(8,15)\\\\[-0.35em] ~\dotfill\\\\ M=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill](/tpl/images/0250/1270/0e78b.png)
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Find the point, m, that divides segment ab into a ratio of 2: 1 if a is at (-1, 2) and b is at (8, 1...
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