In the ordered pair (12, –7)

a. the abscissa is –7 and the ordinate is 12.
b. the abscissa is –12 and the ordinate is 7.
c. the abscissa is 12 and the ordinate is –7.
d. the abscissa is 7 and the ordinate is –12.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

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