Apples sell for $1.90 per pound, and bananas sell for $0.75 per pound. troy bought some apples and some bananas. together they weighed 3.8 pounds, and cost $5.84. let p represent the number of pounds of apples troy purchased. which equation represents the problem described here?

a. 1.15p + 2.85 = 3.8

b. 1.9p + 0.75 = 3.8

c. 1.15p + 2.85 = 5.84

d. –1.15p + 2.85 = 5.84

1.15p + 285 = 5.84

Step-by-step explanation:

This problem has two equations. Total cost and Total pounds. The cost and the pounds

p = apple pounds

b = banana pounds

Cost

1.90p + .75b =  5.84

Pounds

p + b = 3.8

Now we use the substitute method for system of equations to solve

p + b = 3.8

b = -p + 3.8

Now that we know what b equals, substitute is for b in the cost equation.

1.90p + .75b =  5.84

1.90p + .75(-p+3.8) =  5.84

distribute / multiply  .75 by (-p+3.8)

1.90p +  -.75p + 2.85 =  5.84

Combine the p values

1.15p + 285 = 5.84

answer: -8.2562234e+13