What is the probability of drawing two blue cards if the first card is not included in the second draw? simplify your answer completely

5/14

Step-by-step explanation:

The total number of cards is 8

There are 5 blue cards

P(1st card is blue) = blue/total = 5/8

We take away a blue card

The total number of cards is 7

There are 4 blue cards

P(2nd card is blue) = blue/total = 4/7

The probability of blue blue is P(blue blue ) =

P(1st card is blue)*P(2nd card is blue) =

5/8* 4/7

20/56

We can divide the top and bottom by 4

5/14

"if it is my birthday, then it is snowing"

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1