Find the value of b and c
show work!

b(3x-2x+c) = 9 - 6x+15

b=3

c=5

Step-by-step explanation:

b(3x^{2}-2x+c) = 9x^{2} - 6x+15

Distribute

3b x^2 -6x +bc = 9x^2 -6x +15

Each term must be equal

3bx^2 = 9x^2

3b = 9

Divide by 3

3b/3 = 9/3

b =3

bc = 15

3c =15

Divide by 3

3c/3 = 15/3

c =5

i'm sure goog can you get that answer

no solution

step-by-step explanation:

there is not enough information in the problem to solve.