If r(x)=3x-1 and s(x)=2x+1, which expression is equivalent to (r-s)(6)

4

Step-by-step explanation:

Step 1:  find (r- s) or  r(x) - s(x)

 r(x) - s(x) = 3x - 1 - (2x + 1)

       r(x) - s(x) = 3x - 1 - 2x - 1   (distribute the -1 to 2x and 1)

           r(x) - s(x) =  x - 2        (combine like terms, 3x + (-2x) = x, -1 + (-1) = -2)

          so   r(x) - s(x) = x - 2, or   (r - s)(x) = x - 2

Step 2:  Plug in 6 to 'x' and find (r - s)(x)

  (r - s)(6) =  6 - 2   =   4

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.