How many solutions does the system have?

y= -2x + 1

y= -2x^2 + 1

There are two solutions one of them = 1 and the other = zero

Step-by-step explanation:

∵ y = -2x + 1 and y = + 1

∴ To find how many solution we will solve them by equating them

∴ -2x + 1 = + 1

∴ 2 - 2x + 1 - 1 = 0

∴ - 2x = 0⇒ take 2x common factor

∴ 2x (x - 1) = 0

∴ 2x = 0 ⇒ x = 0

∴ x - 1 = 0 ⇒ x = 1

∴ The system has two solutions 1 and zero

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