Factor completely.

49t^6 - 4k^8

a.) (7t³ + 2k^4)(7t³ - 2k^4)
b.) (7t³ - 2k^4)(7t³ - 2k^4)
³ + 2k^4)(7t³ + 2k^4)

A.) (7t³ + 2k^4)(7t³ - 2k^4)

Step-by-step explanation:

Factor the following:

49 t^6 - 4 k^8

49 t^6 - 4 k^8 = (7 t^3)^2 - (2 k^4)^2:

(7 t^3)^2 - (2 k^4)^2

Factor the difference of two squares. (7 t^3)^2 - (2 k^4)^2 = (7 t^3 - 2 k^4) (7 t^3 + 2 k^4):

 (7 t^3 - 2 k^4) (7 t^3 + 2 k^4)