The length of a picture frame is 6 inches more than the width. for what values of x is the perimeter of the picture frame greater than 156 inches?

x > 36 in

Step-by-step explanation:

         Let x = the width of the picture frame.

Then x + 6 = the length of the frame.

The formula for the perimeter P of a rectangle is'

P = 2l + 2w.

So, the condition is

    2l     + 2w > 156

2(x + 6) + 2x  > 156     Distribute the 2

2x + 12 + 2x  > 156     Combine like terms

       4x + 12  > 156     Subtract 12 from each side

               4x > 144     Divide each side by 4

                x >  36

The perimeter of the picture frame will be greater than 156 in if x > 36 in.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

it is x equals 3   plese mark me really need it

step-by-step explanation: