Locating zeros of polynomial functions ! pl will mark most brainiest

Option 1. (-1, 1 ) is the correct option.

Step-by-step explanation:

The given polynomial function is

To find the real zeros of any polynomial we follow the procedure as below

First we find p/q where p represents the factors of constant term of the polynomial and q represents the factors of the coefficient of highest degree term of the expression.

So factors will be = p/q = ± factors of 2/ ± factors of 2

                                      = ±1, ±2/±1, ±2

So the probable factors are ±1, ±2

Now by putting the values of x in the polynomial

For x = 1

f(x) = 2 - 1 + 1 - 2 = 0

Therefore (x-1) is a factor.

For x = -2

f(x) = 2×16 + 8 -2 -2 = 36

So its not the factor.

For x = -1

f(x) = 2 + 1 - 1 - 2 = 0

Therefore for x = -1 and x= 1 f(x) is zero.

4444444444444 i think

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.