Use factoring to solve the quadratic equation x2 − 2x − 3 = 12.

Step-by-step explanation:

You have the following quadratic equation given in the problem:

You must make the equation equal to zero, as following:

Add like terms:

Now, to factor the equation, you must find two numbers whose sum is -2 and whose product is -15. Therefore, you have:

x = -3 and x = 5

Step-by-step explanation:

x² − 2x − 3 = 12

x² − 2x − 3  - 12 = 0

x² − 2x − 15 = 0

Product = -15

sum = -2

Factors  are: 3, -5

So the equation becomes;

x² − 2x − 15 = 0

x² + 3x - 5x − 15 = 0

(x² + 3x) - (5x + 15) = 0

x(x + 3) - 5(x + 3) = 0

(x + 3)(x - 5) = 0

∴ (x + 3) = 0

    x = -3  

          or

   (x - 5) = 0

    x = 5

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5