The correct answer is infinite solutions
Step-by-step explanation:
It is given that,
-3x+y=10 (1)
-6x+2y=20 (2)
eq (1) x 2 ⇒ -6x+2y=20 (3)
from this we get eq(2) and eq(3) are same.
Therefore these two equation have infinite solution.
To find the solution using substitution
-3x+y=10 (1)
y = 3x +10
Substitute the value of y in eq(2)
-6x+2y=20 (2)
-6x +2(3x +10) = 20
-6x + 6x + 20 = 20
20 = 20