202 tickets are sold. a child costs $6 and an adult ticket costs $10. how may tickets of each were sold if the receipts totaled $1708?

The number of child tickets = 78 and the number of adult tickets = 124

Step-by-step explanation:

Let the number of child ticket is x and the adult ticket is y

∴ x + y =202 ⇒ (1)

∵ The cost of child ticket is $6 and adult ticket is $10

∴ 6x + 10 y = 1708 ⇒ (2)

Solve the system of equations (1) and (2)

Multiply (1) by -6 to eliminate x

∴ -6x + -6y = -1212 ⇒ (3)

Add (2) and (3)

∴ 4y = 496

∴ y = 124

Substitute the value of y in (1)

∴ x + 124 = 202 ⇒ x = 202 - 124 = 78

∴ The number of child tickets = 78 and the number of adult tickets = 124

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

215.92 dollars is the answer