Solve the equation. check your answer. if necessary, round to 3 decimal places

in (t - 1) + in x^2 = 6, x=

algebra 2

x ≈ ±20.086/√(t - 1)  

Step-by-step explanation:

ln(t - 1) + ln(x²) = 6

Recall that lnu + lnv = ln(uv). Then  

ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6

Take the natural antilogarithm of each side

(t - 1)x² = e⁶

Divide each side by t - 1

x² = e⁶/(t-1)

Take the square root of each side

x = ±e³/√(t - 1)

x ≈ ±20.086/√(t - 1)

60

step-by-step explanation: