Which of the given functions could this graph represent?

a. f(x) = x(x − 1)(x + 1)
b. f(x) = (x − 1)(x − 2)(x + 1)(x + 2)
c. f(x) = x(x − 1)(x − 2)(x + 1)(x + 2)
d. f(x) = x(x − 1)(x − 2)

The answer is B. f(x) = (x − 1)(x − 2)(x + 1)(x + 2)

B. f(x) = (x − 1)(x − 2)(x + 1)(x + 2)

Step-by-step explanation:

Choice A will be a transformation of the function f(x) = x³.  The parent function goes from the third quadrant through the origin into the first quadrant.  This is not a cubic function.

Choice C will be a transformation of the function f(x) = x⁵.  The parent function goes from the third quadrant through the origin into the first quadrant.  This is not one of those functions.

Choice D will be a transformation of the function f(x) = x³.  This is not a cubic function.

Choice D will be a transformation of the function f(x) = x⁴.  These functions go from the second quadrant across the y-axis into the first quadrant.  This is a quartic function.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

slope= 1

y-inter slope= 0

x       y

o     0

1       1

2     2

ect.

step-by-step explanation: