2x+5y=-15 and 5x+2y=-6 how could you solve this system using elimination

x = 0, y = -3

Step-by-step explanation:

-2x + 5y = -15   →   5(-2x + 5y = -15)   →  -10x + 25y = -75

5x + 2y =  -6   →    2(5x + 2y =  -6)    →   10x +  4y = -12

                                                                          29y = -87

                                                                              y = -3

Input y = -3 into one of the original equations to solve for x:

-2x + 5(-3) = -15

-2x - 15 = -15

-2x       =  0

  x       =  0

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )