Two motorcyclists left point a for point b at the same time. the speed of one motorcyclist was 1.5 times greater than the speed of the other one. the motorcyclist, who reached point b first, immediately went back. he met the other motorcyclist in 2 hours and 24 minutes after the departure from point a. the distance between point a and point b is 120 mi. what is the speed of the cyclists and the distance from the point they met and point b?

40 mph, 60 mph, 24 miles

Step-by-step explanation:

Let x mph be the speed of the slower motorcyclist, then 1.5x mph is the speed of the faster motorcyclist.

Both motorcyclists were travelling 2 hours 24 minutes = 2.4 hour. The slower motorcyclist drove miles and the faster motorcyclist drove miles. In total, they both drove two distances from the point A to the point B, so

The slower motorcyclist drove

miles, so the distance from the point they met and point B is

miles.

answer. d.289 hope that

the answer i believe is 27 units.

step-by-step explanation: