Cos(x+y)cos(x-y)=cos^2(x)-sin^2(y)< br /> verify the identity

Verified.

Step-by-step explanation:  The given identity involving trigonometric ratios is

We have

Therefore, L.H.S. = R.H.S.

Thus, the given identity is verified.

cos(x+y)sin(x-y) = cos²x-sin²y ⇒ L.H.S = R.H.S

Step-by-step explanation:

L.H.S:

∵ cos(x+y)cos(x-y) = (cosxcosy - sinxsiny)(cosxcosy + sinxsiny)

Multiply the brackets ⇒ the answer is difference of two squares

∴ = cos²xcos²y - sin²xsin²y

∵ cos²y = 1 - sin²y and sin²x = 1 - cos²x

∴ cos²xcos²y - sin²xsin²y = cos²x (1 - sin²y) - (1  -cos²x) sin²y

∴ = cos²x - cos²xsin²y - sin²y + cos²xsin²y

∵ -cos²x sin²y will cancel cos²xsin²y ⇒ same terms with different sign

∴ = cos²x - sin²y = R.H.S

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

x = -2

y = 848

step-by-step explanation:

plug in the numbers