Write an equation in slope-intercept form that is parallel to the line 3x + 2y = 1 and passes through the point (1, 0). a)
y = 3/ 2 x + 2 b) y = − 2 /3 x + 1 c) y = − 2/3 x - 1 d) y = − 3/2 x + 3 /2

D)y = − 3/2 x + 3 /2

Step-by-step explanation:

3x+2y =1

We need to get this in slope intercept form (solve for y)

Subtract 3x from each side

3x-3x +2y = -3x+1

2y = -3x+1

Divide by 2

2y/2 = -3/2x+1/2

The slope is -3/2

We want a line that is parallel so the slope is the same

m = -3/2

We an use point slope form since we have the slope and a point

y - y1 = m(x-x2)

y - 0 = -3/2(x-1)

Distribute

y = -3/2x +3/2

what? ?

what type of question is thiss

step-by-step explanation:

the system of inequalities is

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

the equation of the dashed line is

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

the equation of the solid line is

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

step 3

the system of inequalities is