The y-coordinate of the vertex of f(x)=-x^2+6x+5 is f(3). true or false.

False, it's f(-3)

Step-by-step explanation:

the standard formula for a quadratic equation is

y = ax² + bx + c

The formula for the vertex is

(x, y) = (-b/2a, f(-b/2a))

First Step:  Use x = -b/2a to find the x-coordinate of the vertex

x = -6/(2*1)

 x = -3

Now plug that into the equation to find the y-value

f(-3) = (-3)² + 6(-3) + 5

   f(-3) = 9 - 18 + 5

     f(-3) = -4

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )