Find the value or values of x in the quadratic equation x2 = 6x – 9. a. x = 9 b. x = 3 c. x = –3, x = 2 d. x = 0, x = 1 mark for review

  B.  x = 3

Step-by-step explanation:

The equation can be rearranged to ...

  x² -6x +9 = 0

  (x -3)² = 0 . . . .show as the square it is

  x -3 = 0 . . . . . take the square root*

  x = 3 . . . . . . . . add 3

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* If the root were non-zero, there would be two of them: ±√( ). That would give rise to two possible values of x. That is not the case here, so there is only one solution.

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In the attached graph, the red curve represents the left side of the equation. The blue line represents the right side. They are equal at the one point where they intersect: (3, 9). That means when x=3, the equation becomes 9=9.

the answer is two. hope this !