Which factor of x2 + 8x- 48?
a.(x-6)
b.(x+4)
c.(x-16)
d.(x+12)

(x + 12)

Step-by-step explanation:

Factor the following:

x^2 + 8 x - 48

The factors of -48 that sum to 8 are 12 and -4. So, x^2 + 8 x - 48 = (x + 12) (x - 4):

 (x + 12) (x - 4) thus the Answer is d:)

y∈r, 8> y≥0

hope i !

p.s the first bit only matters if you know what that means.

p.p.s brainliest would really