Can someone me with this i need it asap

Part A)

(1, 1)  (1, 2)  (1, 3)   (1, 4)  (1, 5)  (1, 6)

(2, 1)  (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1)  (3, 2)  (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2)   (4 3)  (4, 4)  (4, 5)  (4, 6)

(5, 1) (5, 2)  (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Part B)

a) 1/36

b) 1/6

Step-by-step explanation:

Part A) Here is the sample when we rolling two dice.

(1, 1)  (1, 2)  (1, 3)   (1, 4)  (1, 5)  (1, 6)

(2, 1)  (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1)  (3, 2)  (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2)   (4 3)  (4, 4)  (4, 5)  (4, 6)

(5, 1) (5, 2)  (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Part B)

a) The total number of possible outcomes = 36

The favorable outcome(getting double sixes) = 1   [That is (6, 6)]

Therefore, the probability of rolling double sixes = The number of favorable outcomes / The total number of possible outcomes

= 1/36

b) The total number of possible outcomes = 36

The favorable outcomes are doubles

(1, 1), (2, 2), (3, 3), (4, 4), (5, 5) and (6, 6)

The number of favorable outcomes = 6

Therefore, the probability of rolling doubles = 6/36

We can simplify it further

= 6/36

= 1/6

Thank you

just sum

10 + 10 = 20