Arestaurant sold tacos and burritos. tacos cost $2 and burritos cost $1. the restaurant sold 48 items for a total of $86. how many burritos were sold

Let’s call tacos t and burritos b... 48 items were sold made of tacos and burritos... ( t + b = 48 )
They sold Tacos for $2 and burritos for $1 ; they made a total of $86. (2t + 1b = 86)

t + b = 48 solved for t is t= 48 - b. Substitute 48 - b for t in the second equation and
2 (48 - b) + b = 86 —> 96 - 2b + b = 86. Combine like terms : 96 - b = 86. Subtract 96 from both SidES of the equation... -b = -10 divide both sides by -1 and b= 10. There are 10 burritos. If we needed to we could take 48-10 and get 38 tacos.

Ican't solve. your equation is impossible. you can't have two equal signs.