The angle of elevation of the top of a tree from a distance of 1000 ft is 25 degrees. how tall is the tree?

466.30 ft

Step-by-step explanation:

Given in the question,

the angle of elevation of the top of a tree from ground = 25°

horizontal distance between angle of elevation and tree = 1000ft

To find,

height of tree( vertical distance from ground to top of tree)

As we can presume for the question that the whole scenario makes a right angle triangle. So, we will use trigonometry functions

Tan Δ = opposite / adjacent

Tan25°= height / 1000

height = 1000 * Tan25°

height = 1000 * 0.466

height = 466.30 ft

So, the height of tree = 466.30 ft

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

step-by-step explanation: it is d