Explain why f(x)= 1/(x-x3)^3 is not continuous at x = 3.

Option b.

Step-by-step explanation:

 1. You have the function given in the problem above.

2. You must keep on mind that. by definition, the division by zero does not exist.

3. The value x=3 makes the denominator of the function f(x) equal to zero. Therefore you can conclude that the function shown in the problem is not defined at x=3.

The answer is the option b.

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

wfirfkfr/jjfi; jn; p/ojkfvlbvmkmgkgkkkgkkg

step-by-step explanation: