Mathematics, 02.10.2019 04:30 saintsfan2004

How much should you invest at 3% simple interest in order to earn $65 interest in 14 months?

Answers: 2

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Answer from: jpsaad00

The investment amount is approximately $63

Step-by-step explanation:

Formula:-

Simple interest I = PNR/100

P - Principle amount

N - Number of years

R - Rate of interest

It is given that,

To find the amount to be invest

we have,

P = ? N 14 months = 7/6 years and R = 3%

P + PNR/100 = 65

P[1 + NR/100] = 65

P[1 + (7*3)/(6*100)] = 65

P[1 +7/200] = 65

P[207/200] = 65

P = (65*200)/207 62.801 ≈ 63

Therefore the investment amount is approximately $63

Answer from: divagothboi

You should invest approximately $1857

Step-by-step explanation:

The simple interest is calculated using the formula;

$I=\frac{P\times T\times R}{100}$

Where P is the principal - the amount to be invested.

We must convert the 14 months to years.

$T=\frac{14}{12}=\frac{7}{6}$ is the time in years.

$R\%=3\%$ is the rate percent.

I=$65 is the interest.

We substitute the values into the formula to get;

$65=\frac{P\times \frac{7}{6}\times 3}{100}$

Simplify to get;

$65\times 100=P\times \frac{7}{2}\times 1$

$\frac{6500\times2}{7}=P$

1857.14=P

You should invest approximately $1857

Answer from: Quest

(2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

step-by-step explanation:

simplify the following:

x/x^2 + 3 x + 2 - (x (x + 1))/(x + 2)

combine powers. x/x^2 = x^(1 - 2):

x^(1 - 2) + 3 x + 2 - (x (x + 1))/(x + 2)

1 - 2 = -1:

x^(-1) + 3 x + 2 - (x (x + 1))/(x + 2)

put each term in 1/x + 3 x + 2 - (x (x + 1))/(x + 2) over the common denominator x (x + 2): 1/x + 3 x + 2 - (x (x + 1))/(x + 2) = (x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)):

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2))

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)) = ((x + 2) + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2)):

(2 + x + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

3 x^2 (x + 2) = 3 x^3 + 6 x^2:

(2 + x + 3 x^3 + 6 x^2 + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

2 x (x + 2) = 2 x^2 + 4 x:

(2 + x + 6 x^2 + 3 x^3 + 2 x^2 + 4 x - x^2 (x + 1))/(x (x + 2))

-x^2 (x + 1) = -x^2 - x^3:

(-x^2 - x^3 + 3 x^3 + 6 x^2 + 2 x^2 + 4 x + x + 2)/(x (x + 2))

grouping like terms, 3 x^3 - x^3 + 6 x^2 + 2 x^2 - x^2 + 4 x + x + 2 = (3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2:

((3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

3 x^3 - x^3 = 2 x^3:

(2 x^3 + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

6 x^2 + 2 x^2 - x^2 = 7 x^2:

(2 x^3 + 7 x^2 + (x + 4 x) + 2)/(x (x + 2))

x + 4 x = 5 x:

answer: (2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

Answer from: Quest

3x + 4y -25 =0 represents the amount of change sianna should recieve

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