Find two consecutive even integers such that the smaller added to two times the larger gives a sum of 16

Integer 1 = 4

Integer 2 = 6

Step-by-step explanation:

If you have two unknown consecutive even integers, you could call them as follows:

Integer 1 = x

Integer 2 = x+2

Your question claims that the smaller added to two times the larger gives a sum of 16.

So

Integer 1 + 2*(Integer 2) = 16

x + 2*(x+2) = 16

x + 2x + 4 = 16

3x = 12

x = 4

Since x is 4, this is your smaller integer. Your larger integer, therefore, would be x + 2, or 4 + 2 = 6.

Integer 1 = 4

Integer 2 = 6

Hope this helps.

answer: no

step-by-step explanation:

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!