Hey guys! can you me how to solve number 16, 18, and 20. because i don’t understand how to solve this

Problem 16

Work Shown:

The exponent 41 divided by 4 leads to

41/4 = 10 remainder 1

The "remainder 1" means that

i^(41) = i^1 = i

The reason why I divided by 4 is because the pattern shown below

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

repeats itself over and over. So this is a block of four items repeated forever.

Problem 18

Work Shown:

Divide 3136 over 4 to get

3136/4 = 784 remainder 0

Therefore,

i^3136 = i^0 = 1

Problem 20

Work Shown:

Combine i^6*i^7 into i^13. We add the exponents here

Now divide by 4 to find the remainder

13/4 = 3 remainder 1

So, i^13 = i^1 = i

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200

the formula of a midpoint between a abd b: