Find the lateral area the regular pyramid. (50 points)

l. a. =

having trouble with these : )

The lateral area the regular pyramid = 18√91 square units

Step-by-step explanation:

It is given a regular hexagon.

From the figure we get the base edge of the pyramid is 6 units

(Since the base of pyramid is regular hexagon

To find the lateral edge

Lateral edge is the hypotenuse of triangle with base = 6 and height = 8

Lateral edge =√(8² + 6²) = √100 = 10

To find the slant height

Slant height is the height of triangle with,

base = 6/2 = 3 and hypotenuse = 10

Slant height = √(10² - 3²) = √(100 - 9) = √91

To find the area of single face

Area = bh/2

b = 6 and h =  √91

Area = (6 * √91)/2 = 3√91

To find the lateral area of pyramid

Lateral area = 6*face area = 6*3√91 = 18√91 square units

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it’s supposed to be -4+45=41

step-by-step explanation: