Y=f(x)=(1/2)^x i need the value of f(-7) and the value of f(5) rounded to the nearest ten thousandth.
the value of f(-7) is .( 0.0078) (0.78) (64) (128) the value of f(5), rounded to the nearest ten thousandth, is . (0.0309) (.0312) (0.313) (32)

f(-7)=128, f(5)=0.0312

Step-by-step explanation:

f(x) is the same thing as y, so correctly written its: f(x)=(1/2)^x

plug -7 in for x: f(-7)=(1/2)^(-7)

simplify by doing (1/2) or .5 raised to the power of -7

f(-7)=128

f(5)=(1/2)^5

(.5)^5

=0.0312

1) Option 4 - 128

2) Option 2 - 0.0312

Step-by-step explanation:

Given : Expression

To find : The value of f(-7) and the value of f(5) rounded to the nearest ten thousandth?

Solution :

The given expression is

1) Substitute x=-7

As

Therefore, Option 4 is correct.

2) Substitute x=5

Therefore, Option 2 is correct.

12cm

the answer is d

hi im bob : l

step-by-step explanation: