What are the zeros of the polynomial function?

The zeros are 4,12

Step-by-step explanation:

To find the zeros, we set the function equal to zero

0=x^2 -16x+48

What two numbers multiply together to give us 48 and add together to give us -16

-4*-12 = 48

-4+-12 = -16

0= (x-4) (x-12)

Using the zero product property

x-4 = 0     x-12 = 0

x=4  x=12

The zeros are 4,12

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i