Me?
y=2(x-5)^2-8
solve the equation for when y=10, show your work algebraically.

Step-by-step explanation:

I've included a graph to confirm the solution.

10 = 2(x - 5)^2 - 8                     Subtract 10 from both sides.

10-10 = 2(x-5)^2 - 8 - 10           Switch

2(X - 5)^2 - 18 = 0                    Divide through by 2

2(x - 5)^2/2  - 18/2 =0

(x - 5)^2 - 9 = 0                        Expand the brackets.

x^2 - 10x + 25 - 9 = 0               Collect like terms

x^2 - 10x + 16  = 0                    Factor

(x - 8)(x - 2) = 0

x = 8

x = 2  

red: 2(x - 5)^2 -8

green: y = 10

lol we need to see what the question is asking about

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)