Ascientist is growing bacteria in a lab for study. one particular type of bacteria grows at a rate of y=2t^2+3t+500. a different bacteria grows at a rate of y=3t^2+t+300. in both of these eqiations y is the number of bacteria after t minutes. when is there an equal number of both types of bacteria.

ANSWER

Approximately after 15 minutes.

EXPLANATION

The growth rate of the first bacteria is

The growth rate of the first bacteria :

To find the time that, there will be an equal number of bacteria, we equate the two equation;

We solve for t to get,

Or

We discard the negative value.

This implies that,

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

d

step-by-step explanation: