Soybean mean is 14% protein; cornmeal is 7% protein. how many pounds of each should be mixed together in order to get 280-lb mixture that is 13% protein?

I have to form a couple of equations in order to solve it.

let the amount of soybean in the mixture be x and that of cornmeal be y

Step-by-step explanation:

x+y = 280

y = 280 - x

x*(14/100) + y*(7/100) = 280*(12/100)

Multiplying the whole equation by 100;

14x + 7y = 3360

in this equation,put y = 280 - x

14x +7 (280-x) = 3360

14x +1960 - 7x = 3360

14x - 7x = 3360 - 1960

7x = 1400

x = 200lbs

y = 280 - x

= 280 - 200

= 80 lbs

Inorder to make a 280lbs mixture having 12% protein, we should mix 200lbs of soyabean and 80 lbs of cornmeal

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6