Write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation.

(-5,8); y=1/5x-2

write an equation for the perpendicular line in slope-intercept form.

y = -5x - 17

Step-by-step explanation:

Linear equations, or lines, that are perpendicular to each other have opposite reciprocals for the value of slope.  For the given line, y = 1/5x - 2, the slope is 1/5 and the opposite reciprocal is -5.

Given the value of the slope and a given point on the second line, you can solve for 'b':

y = mx + b

8 = (-5)(-5) + b

8 = 25 + b

-17 = b

y = -5x - 17

its d. the first coordintaes are 10,32

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)