So i solved this thing up to the point where i have x^2-x-42=0 but i have no idea how to find x from here? i mean i should but i don't?

x = 7

Step-by-step explanation:

x(x-1) = 42 (Area)

By trial and error method let's take x = 7

We get

7(7-1) = 42

7 x 6 = 42

42 = 42

Therefore LHS = RHS

Therefore it's 7

Hope this helps

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x = - 6 , x = 7

Step-by-step explanation:

given

x² - x - 42 = 0

Consider the factors of the constant term (- 42) which sum to give the coefficient of the x- term ( - 1)

The factors are - 7 and + 6, since

- 7 × + 6 = - 42 and - 7 + 6 = - 1, hence

x² - x - 42 = (x - 7)(x + 6) and so

(x - 7)(x + 6) = 0

Equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 6 = 0 ⇒ x = -6

Solutions are x = - 6, x = 7