fill in the missing

given: d is the midpoint of segment bf, segment bc || segment ef

prove: δbdc ≅ δfde

ΔBDC ≅ ΔFDE

Step-by-step explanation:

The proof is given below

To prove ΔBDC ≅ ΔFDE

Statements                           reasons

1). BC║EF                         -  Given

2).  D is the mid point         - Given

3). BD = DF                        - Definition of midpoint

4). <BDC = <FDE               - Vertically opposite angles are equal

5).  <CBD = <DFE              - alternate interior angles of parallel lines are                                      

                                               congruent

6). ΔBDC ≅ ΔFDE                 ASA rule

Therefore ΔBDC ≅ ΔFDE. Hence the proof.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

is there any photos or whatever?