What is the solution set of the quadratic inequality 4(x+2)^2< 0

Solution set of the quadratic inequality is { x : x ∈ R and x < -2 }

Step-by-step explanation:

Given Quadratic inequality ,

We have to find solution set of the given quadratic inequality.

consider,

transpose 4 to RHS

Square root both side,

transpose 2 to RHS

x < -2

Solution set of the quadratic inequality = { x : x ∈ R and x < -2 }

Therefore, Solution set of the quadratic inequality is { x : x ∈ R and x < -2 }

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb