The path of a cannonball is a parabola modeled by the equation y=55+x-0.002x squared where x and y are both measured in feet. in this model, the cannonball starts at the point (0,55) and travels to the right. the ground is represented by the x-axis. sketch a graph of the cannon ball's path, and determine the horizontal distance traveled by the ball before it hits the ground.

The horizontal distance traveled by the ball before it hits the ground is 550 ft

The graph in the attached figure

Step-by-step explanation:

we have

Using a graphing tool

we know that

The horizontal distance traveled by the ball before it hits the ground is equal to the horizontal distance from the origin to the x-intercept of the graph

so

The horizontal distance is 550 ft

see the attached figure

22 dimes and 9 nickels

step-by-step explanation:

y > 1/3x

y < = -x + 4

hope this : )