Solve the following system of equations. 3x + 2y - 5 = 0 x = y + 10 make sure there are no spaces in your answer. include a comma in your answer. {( a0 )}

(5, - 5)

Step-by-step explanation:

Given the 2 equations

3x + 2y - 5 = 0 → (1)

x = y + 10 → (2)

Substitute x = y + 10 in (1)

3(y + 10) + 2y - 5 = 0 ← distribute and simplify left side

3y + 30 + 2y - 5 = 0

5y + 25 = 0 ( subtract 25 from both sides )

5y = - 25 ( divide both sides by 5 )

y = - 5

Substitute y = - 5 in (2) for corresponding value of x

x = - 5 + 10 = 5

Solution is (5, - 5)

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3